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Factorise 1 + b ^3 + …

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Factorise 1 + b ^3 + 8 C^3- 6bc.
  • 2 answers

Ankita Dubey 5 years, 1 month ago

Answer =[(1+b+2c) (1+b^2+4c^2-b-2bc-2c)]

Ankita Dubey 5 years, 1 month ago

[x^3+y^3+z^3=(x+y+z) (x^3+y^3+z^3-xy-yz-zx)] formula
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