a car moving at 40km/h is …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
a car moving at 40km/h is to be stopped by applying brakes in the next 4m . if the car weighs 2000kg, what average force must be applied on it?
Posted by Tanishka Jain 8 years, 2 months ago
- 2 answers
Payal Singh 8 years, 2 months ago
Initial velocity u = 40km/h = {tex}{40000\over 3600 }={100\over 9}m/s{/tex}
Distance to be covered before stopping s = 4m
Final velocity v = 0
We know
{tex}v^2-u^2= 2as{/tex}
=> {tex}{10^4\over 81}= 2a\times 4{/tex}
=> {tex}a = {1250\over 81}{/tex}m/s2
Mass of car m = 2000 kg
force applied = ma = {tex} {1250\over 81} \times 2000 = 30864.19\ N{/tex}
Related Questions
Posted by Nekita Baraily 1 year, 1 month ago
- 2 answers
Posted by Mansi Class 9Th 1 year, 1 month ago
- 0 answers
Posted by M D 1 year, 1 month ago
- 1 answers
Posted by Pankaj Tripathi 1 year, 1 month ago
- 1 answers
Posted by Mohammed Javith 1 year, 1 month ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sahdev Sharma 8 years, 2 months ago
Mass of car m = 2000 kg = 2{tex}\times 10^3 kg{/tex}
Initial velocity u = 40km/h = {tex}{40000\over 3600 }={100\over 9}m/s{/tex}
Distance to be covered before stopping s = 4m
Final velocity v = 0
We know
{tex}v^2-u^2= 2as{/tex}
=> {tex}{10^4\over 81}= 2a\times 4{/tex}
=> {tex}a = {1250\over 81}{/tex}m/s2
force applied = ma = {tex} {1250\over 81} \times 2000 = 30864.19\ N{/tex}
0Thank You