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There is a slide in a …

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There is a slide in a park . One of its side walls has been painted in some colour with a messge "keep the park green and clean "if the sides of the walls are 15m,11m,and 6m,find the area painted in colours.

Posted by Lakshita Teotia 6 years, 2 months ago

CBSE > Class 09 > Mathematics

3 answers

Sia ? 6 years, 2 months ago

Since, sides of coloured triangular wall are 15 m, 11 m and 6 m.
{tex}\therefore{/tex} Semi-perimeter of coloured triangular wall
S ={tex}\frac{15+11+6}{2}{/tex}={tex}\frac{32}{2}{/tex}=16 m
Now, Using Heron’s formula,
Area of coloured triangular wall
={tex}\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}{/tex}
={tex}\sqrt{16\left( 16-15 \right)\left( 16-11 \right)\left( 16-6 \right)}{/tex}
={tex}\sqrt{16\times 1\times 5\times 10}{/tex}
={tex}20\sqrt{2}{{m}^{2}}{/tex}
Hence area painted in blue colour = {tex}20\sqrt{2}{{m}^{2}}{/tex}

Rohan Bamniya 6 years, 2 months ago

20√2

Angadh Kamboj 6 years, 2 months ago

First we find the semi perimeter of its all side that is S=a+b+c/2 S=15+11+6/2 S=32/2=26 So semi perimeter of all sides is 16 Now using herons formula Underroot s(s-a) (s-b) (s-c) Put the value 16(16-15) (16-11) (16-6) 16×1×5×10 These all are underroot Now take common from that What we can write to 16 4×4 So put 4×4×5× now expand 10 that is = 5×2 4×4×5×5×2 Now take 4 and 5 out of the root And 2 in root 4×5 underroot 2 that is 20 undertoot 2 cm²

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