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Explain work energy theorem

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Explain work energy theorem
  • 3 answers

Udit Varshney 5 years, 9 months ago

W=½v²-½u²

Shivam Dangwal 5 years, 9 months ago

It states that the work done by an object is the change in kinetic energy of the body i.e. difference in final KE and inital KE. W=1/2mv^2-1/2mu^2 W=1/2m(v^2-u^2) Hope you got the feel of the topic.

Khushi Rajput 5 years, 9 months ago

Work done by a force on a body is equal to the change in the kinetic energy of the body Let us consider a body of mass M moving with the initial velocity u and when a constant force F is applied on it its velocity become V dw=f×dx dw=m dv/dt × dx dw=mdv(dx/dt) dw=mvdv On integrating |dw=|mvdv W=m |vdv W=m(v2)/2 W=m(v2-u2)/2 W=1/2mv2-1/2mu2
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