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Find the sum of first fifty …

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Find the sum of first fifty natural numbers

Posted by Pankaj Jain 6 years, 2 months ago

CBSE > Class 10 > Mathematics

7 answers

Yogita Ingle 6 years, 2 months ago

(1) 1+2+3+4+………………+48+49+50.

If we start adding the first & the last numbers

1+50= 51

2+49 = 51

3+ 48 = 51

4+ 47 = 51………..

This way if we continue.. Towards the end we get…

24 + 27 = 51

25 + 26 = 51

That shows, by adding them we get 51, 25 times.

So the total will be 51 * 25 = 1275 .

(2) So we can frame a formula now, whenever , the sum of first ’n’ numbers are to be found out…

SUM = n/2 * (n+1) = 50/2*(50+1) = 25*51= 1275

[3] or, The sum of any ‘n’ numbers = Sn =

n/2 { 2a + (n-1)d} = 50/2 {(2+ 49*1}= 25*51= 1275

Shivansh Gupta 6 years, 2 months ago

1275✌✌??

?✌ 6 years, 2 months ago

Emoji nhii Diya?

Rahul Singh 6 years, 2 months ago

Sorry bro my multiplication is wrong,emoji is correct and rest all r correct

?✌ 6 years, 2 months ago

25×51=1275?

?‍♀Cindrella ?‍♀... 6 years, 2 months ago

...

Rahul Singh 6 years, 2 months ago

Ap:1,2,3......... Here a=1,d=1,n=50 Sn=n/2[2a+(n-1)d] =50/2[2+(50-1)1] =25[2+49] =25(51) =2499

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