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If sin 3A=cos(A-16) where 3A <90 …

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If sin 3A=cos(A-16) where 3A <90 degree findA

    • Posted by Yadav Monu 6 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 6 years, 3 months ago

    Qustion: If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A.

    Solution:

    Sin 3A = cos (A-26 )

    cos (90 - 3A) = cos (A-26) [ sinA = cos (90- A )
    By comparison

    90-3A = A-26

    90+26=A+3A
    116=4A

    A= 29

    1Thank You

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