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Find the base of an isosceles …

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Find the base of an isosceles triangles whose area is 12cm and the length of one of the equal side is 5cm.
  • 1 answers

Yogita Ingle 5 years, 1 month ago

Base: ?

Area: 12 cm sq

side 1: 5 cm

The formula of area is :

1/2 × base × height

 let the base be 2b and height be h.

 b × h= 12

h= 12/b

use Pythagoras theorem:

b²+h²= 5²

so b²+ 12²/b²= 25
so next your equation will be: b( power 4) - 25b²+144=0

So next (b + 4)(b – 4)(b + 3)(b – 3) = 0

Neglecting the negative values, b could be 3 giving h = 4
or b could be 4 giving h = 3
This means the whole base could be 6 and the height is 4
OR the whole base could be 8 and the height is 3

 

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