A 2.0cm tall object is placed …

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A 2.0cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 10cm. The distance of the object from the mirror is 15 cm. Find the nature,positionand size of the image formed. Represent the situation with the help of a ray diagram. (Answer is V=-30.0cm and h' =-4cm)

Give me solution please

Posted by Akshay Sehrawat 8 years, 5 months ago

CBSE > Class 10 > Science

1 answers

Poulami Dasgupta 8 years, 5 months ago

Height of object(h_o)= 2cm

Focal length(f) = —10cm(sign convention for concave mirror)

Object distance(u) = —15cm(sign convention for concave mirror)

Using Mirror formula,

{tex}{1\over v}+{1\over u}={1\over f}{/tex}

{tex}{1\over v} —{1\over15}={1\over—10}{/tex}

{tex}{1\over v}={1\over 15}—{1\over 10}{/tex}

{tex}{1\over v}={—1\over30}{/tex}

v=—30cm

{tex}{—v\over u}={hi\over ho}{/tex}( where hi = height of image and ho = height of object)

{tex}{30\over —15}={hi\over 2}{/tex}

{tex}{—2}={hi\over2}{/tex}

hi = —4 cm

The nature of image is real and inverted

0Thank You

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CBSE > Class 10 > Science