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sinA÷ sinA÷ cotA+cosecA=2+cotA-cosecA

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sinA÷ sinA÷ cotA+cosecA=2+cotA-cosecA

    • Posted by Harsh Gupta 6 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 3 months ago

    LHS = 
    sinA/(cotA+cosecA)
    = (sinA)(cosecA-cotA)/(cosecA+cotA)(cosecA-cotA)
    = (1-cosA)/(cosec2A-cot2A)
    = (1-cosA)/1 = 1-cosA
    RHS = 
    2+(sinA)/(cotA-cosecA)
    = 2+(sinA)(cotA+cosecA)/(cotA-cosecA)(cotA+cosecA)
    = 2+(cosA+1)/(cot2A-cosec2A)
    = 2+(cosA+1)/(-1)
    = 2-cosA-1
    = 1-cosA
    LHS=RHS=1-cosA
    Hence proved

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