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A battery of emf e and …

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A battery of emf e and internal resistance r gives a current of 0.5A with an external resistor of 12ohm and current of 0.25 A with an external resistor of 25ohm.Find its emf and internal resistance.

    • Posted by Shubhdeep Paul 6 years, 3 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Sia ? 6 years, 3 months ago

    As we know
    {tex}I = \frac{E}{{R + r}}{/tex}
    Now, {tex}0.5 = \frac{E}{{12 + r}}{/tex} and {tex}0.25 = \frac{E}{{25 + r}}{/tex}

    1. Dividing, {tex}\frac{{0.5}}{{0.25}} = \frac{{25 + r}}{{12 + r}}{/tex}
      or, {tex}2 = \frac{{25 + r}}{{12 + r}}{/tex} or {tex}r = 1\Omega{/tex}
    2. {tex}0.5 = \frac{E}{{12 + 1}} \Rightarrow{/tex} E = 6.5 V

    1Thank You

    Aman Shrivastava 6 years, 3 months ago

    Not at answer

    1Thank You

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