AOB is a straight line then …
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Posted by Manvi Rawat 5 years, 2 months ago
- 2 answers
Sia ? 5 years, 2 months ago
{tex}\angle AOC{/tex} + {tex}\angle BOC{/tex} = {tex}\angle AOB{/tex}
{tex}\angle AOC{/tex} + {tex}\angle COB{/tex} = 180o (liner pair)
6x + 30o + 4x = 180o
10x + 30o = 180o
10x = 180o - 30o
10x = 150o
x = {tex}\frac {150}{10}{/tex} = 15
x = 15o
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Kunal Thakur 5 years, 2 months ago
0Thank You