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If sin A =9/41,comput3 cos A …

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If sin A =9/41,comput3 cos A and tan A

    • Posted by Jayasree Ammu 6 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Prince Kumar 6 years, 3 months ago

    SinA=1/cos =41/9

    0Thank You

    Sia ? 6 years, 3 months ago

    Given, {tex}\angle{/tex}B = 90°.
    Let BC = 9 and AC = 41

    sin A{tex}= \frac { \text { Perpendicular } } { \text { Hypotenuse } } = \frac { \mathrm { BC } } { \mathrm { AC } } = \frac { 9 } { 41 }{/tex}
    By Pythagoras' theorem, we have
    AC2 = AB2 + BC2
    {tex}\Rightarrow{/tex}AB2= AC2 - BC2
    = 412 - 92 = 1681 - 81 = 1600
    {tex}\Rightarrow AB = 40{/tex}
    {tex}\cos A = \frac { \text { Base } } { \text { Hypotenuse } } = \frac { A B } { A C } = \frac { 40 } { 41 }{/tex}
    {tex}\tan A = \frac { \text { Perpendicular } } { \text { Base } } = \frac { B C } { A B } = \frac { 9 } { 40 }{/tex}

    0Thank You

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