The diognals of rhombus measure 16cm …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Geeta Sharma 6 years, 3 months ago
- 3 answers
Yogita Ingle 6 years, 3 months ago
Now by seeing this attached picture we can say that 8 cm +8 cm = 16 cm and 15 cm + 15 cm = 30 cm...
since diagonal of a rhombus bisects each other
now by applying Pythagoras theorem we get,
h² = p² + b²
h² = 8² + 15²
h² = 64 + 225
h² = 289
h = √289
h = 17
therefore perimeter of the rhombus ,
= 4 * side
= 4 * 17
= 68 cm
therefore perimeter of the rhombus = 68 cm
Related Questions
Posted by Bhargav Panchal Shantilal Panchal 1 year, 4 months ago
- 2 answers
Posted by Shree Vanshika Reddy Reddy 8 months, 2 weeks ago
- 0 answers
Posted by Harsha Sarji.S 1 year, 2 months ago
- 0 answers
Posted by Vedika Chourasiya 1 year, 2 months ago
- 0 answers
Posted by Dipratna Salunke 1 year, 4 months ago
- 2 answers
Posted by Shivanshu Pandey 1 year, 4 months ago
- 0 answers
Posted by Heena Khatun 1 year, 1 month ago
- 0 answers
Posted by Shree Vanshika Reddy Reddy 3 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Prince Kumar 6 years, 3 months ago
2Thank You