If the linear momentum of a …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Nekita Baraily 1 year, 4 months ago
- 2 answers
Posted by Mohammed Javith 1 year, 5 months ago
- 0 answers
Posted by Mansi Class 9Th 1 year, 5 months ago
- 0 answers
Posted by M D 1 year, 4 months ago
- 1 answers
Posted by Pankaj Tripathi 1 year, 5 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 3 months ago
Let Kinetic energy = k
Momentum = P = mv
Mass = m
{tex}K=\frac{1}{2} m v^{2}=\frac{P^{2}}{2 m}{/tex}
if momentum is increabed by 20%
{tex}\frac{\left(p+\frac{20}{100} p\right)^{2}}{2 m}=\frac{p^{2}(1.2)^{2}}{2 m}=1.44 \mathrm{K}{/tex}= N present kinetic energy{tex} {/tex}
{tex}\frac{\Delta K}{K} \times 100=44 \%{/tex}
{tex}\therefore{/tex} kinetic energy will increase by 44% if momentum is increased by 20%
0Thank You