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Find the freezing point of a …

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Find the freezing point of a solution containing 0.520 gram of glucose dissolved in 80.2 gram given Kf=1.86
  • 2 answers

Gaurav Seth 6 years, 3 months ago

Molecular mass of glucose

C6H12O6=72+12+96C6H12O6=72+12+96

⇒180gmol−1⇒180gmol−1

ΔTf=Kf×WB×1000MB×WAΔTf=Kf×WB×1000MB×WA

⇒1.86×0.520×1000180×80.20⇒1.86×0.520×1000180×80.20

⇒0.067

Ďãřşháñăã Yadav ? ? ? 6 years, 3 months ago

MM of Glucose C6H12O6=72+12+96=180 g/mol. ➡️ ΔTf =Kf×WB×1000/MB×WA ➡️ ΔTf= 1.86×0.520×1000/180×80.20 ➡️ ΔTf =0.067
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