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If k. E of a body …

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If k. E of a body increase by 100 % how much % of momentum will increased

Posted by Deepak Kumar Singh 6 years, 3 months ago

CBSE > Class 11 > Physics

1 answers

Mehak Gautam 6 years, 3 months ago

Kinetic energy = p^2/2m If the momentum increases by 100% , then the p increases to 2p. Substitute p =1 K before increase in momentum = p^2/2m = 1/2m - (1) K' after increase in momentum by 100% = 2p^2/2m= 4/2m - (2) Let p = 1 Divide (2) by (1) and substitute p=1 K'/K = (4/2m) / (1/2m) = 4 ( 2m gets divided by 2m to give 1) K'= 4K ( cross-multiplication) Percentage increase = (K'-K / K) * 100 = (4K-K/K) *100 = (3K /K) *100 = 3*100 = 300% When momentum of a body increases by 100% then its kinetic energy will increase by 300%.

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