Solve the following pair of linear …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Epic Boy Rahul 6 years, 3 months ago
- 1 answers
Test
Related Questions
Posted by Kanika . 1 month ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 3 months ago
The given pair of equations is
px + qy = p - q .....(1)
qx - py = p + q ....(2)
Multiplying equation (1) by p and equation (2) by q, we get
p2x + pqy = p2 - pq....(3)
q2x - pqy = pq + q2.....(4)
Adding equation (3) and equation (4), we get
(p2 + q2)x = p2 + q2
{tex}\Rightarrow \;x = \frac{{{p^2} + {q^2}}}{{{p^2} + {q^2}}} = 1{/tex}
Substituting this value of x in equation (1), we get
p(1) + qy = p - q
{tex}\Rightarrow{/tex} qy = -q
{tex}\Rightarrow \;y = \frac{{ - q}}{q} = - 1{/tex}
So, the solution of the given pair of linear equations is x = +1, y = -1.
Verification, Substituting x = 1, y = -1,
We find that both the equations (1) and (2) are satisfied as shown below:
px + qy = p(1) + q(-1) = p - q
qx - py = q(1) - p(-1) = q + p = p + q
This verifies the solution.
0Thank You