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In a triangle ABC if angle A=45° determine the shortest and largest side of triangle

Posted by Anwesa Mahapatro 5 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 5 years, 2 months ago

We have, {tex}\angle{/tex}A = 45° and {tex}\angle{/tex}B = 70°
{tex}\therefore{/tex} {tex}\angle{/tex}A + {tex}\angle{/tex}B + {tex}\angle{/tex}C = 180^o
{tex}\Rightarrow{/tex} 45^o + 70^o + {tex}\angle{/tex}C = 180^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}C = 180^o - 115^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}C = 65^o
Since the side opposite to the greatest angle is largest. Therefore, side AC is largest. The side opposite to the least angle is the smallest. So, side opposite to {tex}\angle{/tex}A i.e. side BC is the smallest.

3Thank You

Anwesa Mahapatro 5 years, 2 months ago

Angle B's value is not given

0Thank You

ANSWER

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