Chapter 4 physics 4.15 Question solution …
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Sia ? 6 years, 3 months ago
Magnetic field strength, B = 100 G = 100 × 10 - 4 T
Number of turns per unit length, n = 1000 turns m - 1
Current flowing in the coil, I = 15 A
Permeability of free space, {tex}\mu_{0}=4 \pi \times 10^{-7} T m A^{-1}{/tex}
Magnetic field is given by the relation, {tex}B=\mu_{0} n I{/tex}
{tex}\therefore n I=\frac{B}{\mu_{0}}{/tex}
{tex}=\frac{100 \times 10^{-4}}{4 \pi \times 10^{-7}}=7957.74{/tex}
{tex}\approx 8000 \mathrm{A} / \mathrm{m}{/tex}
If the length of the coil is taken as 50 cm, radius 4 cm, number of turns 400, and current 10 A, then these values are not unique for the given purpose. There is always a possibility of some adjustments with limits.
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