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If 3tan 4 equivalent 3 sin theta + 2 cos theta by 3 Sin Theta - 2 cos theta

Posted by Akhil Sinha 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

{tex}3tan\theta = 4{/tex}{tex}\Rightarrow \tan \theta = \frac { 4 } { 3 }{/tex}
Given,
{tex}= \frac { 3 \sin \theta + 2 \cos \theta } { 3 \sin \theta - 2 \cos \theta }{/tex}
{tex}= \frac { 3 \tan \theta + 2 } { 3 \tan \theta - 2 }{/tex}[Dividing numerator and denominator by cos {tex}\theta{/tex}]
{tex}= \frac { \left( 3 \times \frac { 4 } { 3 } + 2 \right) } { \left( 3 \times \frac { 4 } { 3 } - 2 \right) } = \frac { 6 } { 2 } = 3{/tex}

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