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A chemist has one solution which …

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A chemist has one solution which is 50% acid and second solution which is 25% acid how much of each should be mixed to make 10 liters of A 40% acid solution

    • Posted by Harshi Goyal 6 years, 3 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 3 months ago

    Suppose x litres of 50% solution be mixed with y litres of 25% solution.
    According to the question,
    50% of x + 25% of y = 40% of 10
    {tex}\Rightarrow \frac { 50 } { 100 } x + \frac { 25 } { 100 } y = \frac { 40 } { 100 } ( 10 ){/tex}
    {tex}\Rightarrow{/tex} {tex}50x + 25y = 40(10){/tex}
    {tex}\Rightarrow{/tex} {tex}2x + y = 16{/tex}..........(i)
    The amount of each solution adds to {tex}10\ litres{/tex},
    {tex}x + y = 10{/tex}.......(ii)
    Subtract (ii) from (i),
    {tex}\Rightarrow{/tex} {tex}x = 6{/tex}
    Substituting {tex}x = 6{/tex} in (i), we get {tex}y = 4{/tex}
    {tex}\therefore{/tex}{tex}6\ litres{/tex} of 50% solution is to be mixed with {tex}4\ litres{/tex} of 25% solution

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