Cos 45 by sec 30 + …
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Yogita Ingle 6 years, 3 months ago
Given, cos 45/(sec 30 + cosec 30)
= (1/√2)/(2/√3 + 2) {since cos 45 = 1/√2, sec 30 = 2/√3, cosec 30 = 2}
= (1/√2)/{(2 + 2√3)/√3}
= (√3/√2)/(2 + 2√3)
= √3/{√2*(2 + 2√3)}
= √3/(2√2 + 2√3*√2)
= √3/(2√2 + 2√6)
So, cos 45/(sec 30 + cosec 30) = √3/(2√2 + 2√6)
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