Two trains A and B of …
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Posted by Drishti Arora 6 years, 3 months ago
- 13 answers
Drishti Arora 6 years, 3 months ago
#Aditi~ Angel???? 6 years, 3 months ago
#Aditi~ Angel???? 6 years, 3 months ago
#Aditi~ Angel???? 6 years, 3 months ago
#Aditi~ Angel???? 6 years, 3 months ago
Gaurav Seth 6 years, 3 months ago
<i>For train A:</i>
Initial velocity, <i>u</i> = 72 km/h = 20 m/s
Time, <i>t</i> = 50 s
Acceleration, <i>a</i>I = 0 (Since it is moving with a uniform velocity)
From second equation of motion, distance (<i>s</i>I)covered by train A can be obtained as:
s = ut + (1/2)a1t2
= 20 × 50 + 0 = 1000 m
<i>For train B:</i>
Initial velocity, <i>u</i> = 72 km/h = 20 m/s
Acceleration, <i>a</i> = 1 m/s2
Time,<i> t</i> = 50 s
From second equation of motion, distance (<i>s</i>II) covered by train A can be obtained as:
<i>s</i>II = ut + (1/2)at2
= 20 X 50 + (1/2) × 1 × (50)2 = 2250 m
Length of both trains = 2 × 400 m = 800 m
Hence, the original distance between the driver of train A and the guard of train B is 2250 – 1000 – 800 = 450m.
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#Aditi~ Angel???? 6 years, 3 months ago
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