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Find the smallest value of k …

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Find the smallest value of k for real roots xsqure-kx+9

Posted by Rina Kumari 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 6 years, 3 months ago

x² - kx + 9 = ax² + bx + c
a = 1 . b = -K and c = 9
since the eqn has real roots

∴ b²-4ac=0

⇒ (-k)²-4×1×9=0

⇒k²=√36

⇒k=±6

∵the smallest value of k is required

∴k= -6

0Thank You

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