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The area of a rhombus is …

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The area of a rhombus is 96 sq cm. If one if its diagonals is 16 cm, find the length of its side

    • Posted by Sunil Rewar 5 years, 2 months ago

    CBSE > Class 09 > Mathematics
    • 3 answers

    Rupali Singh 5 years, 2 months ago

    Sa of rhombus is 1/2× D1×D2. 96=1/2×16×D2 96×2÷16=D2 D2=16. As we know that diagonals of rhombus bisect each other at right angles. Therefore; By Pythagoras theorem; S1(square)=64+64 S1(Square )=128(root) =11. 3. Similarly each side is 11. 3cm

    0Thank You

    Simran Kaur 5 years, 2 months ago

    If other diagonal is 12 cm.. Diagonals in rhombus bisects at 90°. It forms a right angled triangle... Length of diagonals after bisecting the diagonals=8,6 by diving them in 2 parts... Now, pythagorous theorum, H²=P²+B² H²=8²+6² H²=64+36 H²= 100 H=√100 H= 10 CM SIDE : 10 CM HOPE U UNDERSTAND

    1Thank You

    Simran Kaur 5 years, 2 months ago

    Area of rhombus =1/2 (product of diagonals) 96=1/2*16*x 96=8*x x=96/8 x=12 Length of other diagonal is 12 cm.

    1Thank You

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