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The angle of depression of a …

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The angle of depression of a car, standing on the ground, from the top of a 75m tower, is 30degree. The distance of the car from the base of the tower ?

Posted by Abc Def 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Shiksha P 6 years, 3 months ago

70Route 3

0Thank You

Gaurav Seth 6 years, 3 months ago

Given that the angle of depression is 30° , then angle of elevation is (90 - 30 = 60°). Therefore,

We have,

tan60° = height of tower /distance of the car from the base of the tower

=>√3 = 75/distance of the car from the base of the tower

=>distance of the car from the base of the tower = 75/ √3 or 75√3/(√3√3) = 25√3

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