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Sin 3A. Cos(A-26). Where 3A andA-26 …

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Sin 3A. Cos(A-26). Where 3A andA-26 are acute angle

Posted by Rao Rao 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhay Mathur 6 years, 3 months ago

We know that, Sin(90-theta) =cos theta So,cos(90-3A) can be compared to cos(90-A-26) 90-3A=64-A 90-64=-A+3A 26=2A A=13° from here onwards u can find the value of 3A and vice versa

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CBSE > Class 10 > Mathematics