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Find the value of k, if …

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Find the value of k, if (k+4)xsquare +(k+1) +=0 has equal roots

Posted by Aayush Kamal 6 years, 3 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 3 months ago

We have, (k+4) x² + (k+1)x + 1= 0
Here a = (k+4), b = (k+1), c =1
{tex}\implies{/tex}D = b² -4ac = (k+1)² - 4 (k+4) (1)
= k² +1 + 2k - 4k -16= k² -2k -15
For equal roots, D = 0
{tex}\implies{/tex}k² - 2k -15 = 0
{tex}\implies{/tex}k² - 5k + 3k -15 = 0
{tex}\implies{/tex}k (k - 5) +3 (k - 5) = 0
{tex}\implies{/tex}(k+3) (k-5) = 0
Either k+3 = 0 or k-5 = 0
{tex}\implies{/tex}k = -3, 5

1Thank You

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