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If zeba were youngers by 5 …

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If zeba were youngers by 5 years than what she really is then the square of her age would have been 11 more than 5 times her actual age .what is her age now?
  • 1 answers

Sia ? 6 years, 3 months ago

Let the actual age of Zeba be 'x' years. If her age is 5 years less than the actual, her age would be (x-5) years. Clearly; x ≥5......(1)
According to the question, we have
  (x - 5)2 = 5x + 11
{tex}\Rightarrow{/tex} x2 - 10x + 25 = 5x + 11
{tex}\Rightarrow{/tex} x2 - 15x + 14 = 0
{tex}\Rightarrow{/tex} x2 - 14x - x + 14 = 0
{tex}\Rightarrow{/tex} (x - 14) - 1(x - 14) = 0
{tex}\Rightarrow{/tex} (x - 14)(x - 1) = 0
{tex}\Rightarrow{/tex} x - 14 = 0 or x - 1 = 0
{tex}\Rightarrow{/tex} x = 14 or x = 1
Since x > 5, we have x = 14
Thus, the present age of Zeba is 14 years.

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