Determine the ratio in which the …

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Sia ? 6 years, 3 months ago
Let the ratio be K: 1
Coordinate of P are {tex}\left( {\frac{{3K + 2}}{{K + 1}},\frac{{7K - 2}}{{K + 1}}} \right){/tex}
P lies on the line 2x + y - 4 = 0
{tex} \Rightarrow 2\left( {\frac{{3K + 2}}{{K + 1}}} \right) + \frac{{7K - 2}}{{K + 1}} - \frac{4}{1} = 0{/tex}
{tex} \Rightarrow {/tex} 6K + 4 + 7K - 2 - 4K - 4 = 0
{tex} \Rightarrow {/tex} 9K - 2 = 0
{tex} \Rightarrow K = \frac{2}{9}{/tex} or 2 : 9
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