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A rocket is fired vertically up …

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A rocket is fired vertically up during burning of engine which lost for 50second .A constant acceleration of 20 observed. What is the speed of rocket at the end of 50second .calculate maximum height to which the rocket will reach it begins to fall back take gravity as 9.8meter per second square

    • Posted by Mersal Bharathan 6 years, 4 months ago

    CBSE > Class 11 > Physics
    • 2 answers

    Ranjeet Kumar 6 years, 4 months ago

    v = u + at v = 0 m/s + 20m/s^2 × 50s = 1000 m/s h = (v^2 - u^2)/2a = {(0^2 - 1000^2)/(-2×20)}m = {(1000000)/40}m = 25000 m

    1Thank You

    Ranjeet Kumar 6 years, 4 months ago

    v = u + at >

    1Thank You

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