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A food packet is released from …

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A food packet is released from an helicopter which is rising steadily at 2m/s after two seconds calculate the velocity of the packet and how far it is below the helicopter

    • Posted by Madhu Mitha 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gaurav Seth 6 years, 4 months ago

    Answer:

    It is 19.6 m below the helicopter.

    Explanation:

    Given that,

    Initial velocity = 2 m/s

    Time t = 2 sec

    (I). The velocity of the packet is

    Using equation of motion

    Negative sign shows that the direction of downward.

    (II)The distance covers by the helicopter is

    The distance covers by the packet

    Using equation of motion

    The total distance is

    Hence, It is 19.6 m below the helicopter.

    2Thank You

    ANSWER
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