The perimeter of two similar triangles …

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Sia ? 6 years, 3 months ago
According to question it is given that triangles ABC and PQR are similar.
Also, perimeter of ∆ ABC = 32 & Perimeter of ∆ PQR = 24
Therefore,
{tex}\frac { \text { Perimeter } ( \triangle A B C ) } { \text {Perimeter } ( \triangle P Q R ) }{/tex}{tex}= \frac { A B } { P Q }{/tex}
{tex}\Rightarrow \frac { 32 } { 24 } = \frac { A B } { 12 }{/tex}
{tex}\Rightarrow A B = \frac { 32 \times 12 } { 24 }{/tex}
= 16 cm
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