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Evaluate: Sin^2 63°+ sin^2 27° ÷ …

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Evaluate: Sin^2 63°+ sin^2 27° ÷ cos^2 17°+cos^2 73°

Posted by Aayush Jain 6 years, 3 months ago

CBSE > Class 10 > Mathematics

3 answers

Aayush Jain 6 years, 3 months ago

Thank u..☺

0Thank You

Ã.P.W.B.Đ ⚡ 6 years, 3 months ago

First of all I would make it clear that Sin(90-a)= cos a. So, sin^2 63°would be cos^2 17° and cos^2 17°=sin^2 73° In the expression given in the question, (Cos^2 17°+sin^2 17°)/(sin^2 73°+cos^2 73) Since sin^2 a+cos^2 a=1, it would become 1/1=1 Hence, the answer is 1.

2Thank You

Aayush Jain 6 years, 3 months ago

Plz ans..

1Thank You

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