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Prove that sin²6x-sin²4x = sin2x sin10x

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Prove that sin²6x-sin²4x = sin2x sin10x

    • Posted by Tripti Verma 6 years, 4 months ago

    CBSE > Class 11 > Mathematics
    • 3 answers

    Nitin Tiwari 6 years, 4 months ago

    Taking RHS side Sin2x sin10x Sin(6x-4x) sin(6x+4x) (Sin6xcos4x - cos6xsin4x)(sin6xcos4x+cos6xsin4x) : (since-sin(A+B)=sinAcosB+sinBcosA)(sin(A+B)=sinAcosB- sinBcosA) Sin^2(6x)cos^2(4x) - cos^2(6x)sin^2(4x) Sin^2(6x)(1 - sin^2(4x)) - (1 - sin^2(6x))sin^2(4x) Sin^2(6x) - sin^2(4x)sin^2(4x) - sin^2(4x) + sin^2(6x )sin^2(4x) Sin^2(6x) - sin^2(4x) Hence . Proved

    0Thank You

    Tripti Verma 6 years, 4 months ago

    Thank you?

    1Thank You

    Rahul Raj 6 years, 4 months ago

    LHS= sin(6x-4x)sin(6x+4x) =sin2xsin10x = RHS

    2Thank You

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