from each corner of a square …

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Sia ? 6 years, 4 months ago
Area of a remaining portion of the square = Area of square - (4 {tex}\times{/tex} Area of a quadrant + Area of a circle)
{tex}= 4 \times 4 - \left[ 4 \times \frac { 90 } { 360 } \times \frac { 22 } { 7 } \times 1 ^ { 2 } + \frac { 22 } { 7 } \times \left( \frac { 2 } { 2 } \right) ^ { 2 } \right]{/tex}
{tex}= 16 - 2 \times \frac { 22 } { 7 }{/tex}
{tex}= \frac { 68 } { 7 } \mathrm { cm } ^ { 2 }{/tex}
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