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find the some of two consecutive postive integers sum of whose squares is 365 

    • Posted by Anusga Ramasamy 9 years ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Rashmi Bajpayee 9 years ago

    Let one of the consecutive number be x.

    Therefore other consecutive number be (x + 1)

    According to question,

    (x)2 + (x + 1)2 = 365

    x2 + x2 + 2x + 1 = 365

    2x2 + 2x - 364 = 0

    x2 + x - 182 = 0

    x2 + 14x - 13x - 182 = 0

    x(x + 14) - 13(x + 14) = 0

    (x + 14)(x - 13) = 0

    x = -14 (neglected), x = 13

    Therefore required two positive integers are 13 and 14.

    2Thank You

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