Solve the following pair of equations …
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Sia ? 6 years, 4 months ago
2x + 3 y = 12
<th scope="row">x</th> <th scope="row">y</th>3y = 12 - 2x
or, {tex}y = \frac { 12 - 2 x } { 3 }{/tex}
If x = 0, we have y = 4
If x = 6,we have y = 0
If x = 3 , we have y = 2
The solution table is as follows:
x - y = 1
<th scope="row">x</th> <th scope="row">y</th>or, y = x - 1
If x = 0, we have y = -1
If x = 1, we have y = 0
If x = 3, we have y = 2
The solution table is as follows:
Plotting the above points and drawing the lines joining them, we get the following graph.
The two lines intersect each other at point (3, 2).
Hence, x = 3 and y = 2.
{tex}\triangle A B C{/tex} is the region between the two lines represented by the given equations and the X-axis.
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