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Find K if kx (x-3)+8=0 has …

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Find K if kx (x-3)+8=0 has real and equal roots

    • Posted by Sukhbir Sandhu 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Shaik Haneef 6 years, 4 months ago

    Kx²-3x+8=0 Given condition : real and equal roots ie.,D=0 or b²-4ac =0 a=k, b=-3k c=8 b²-4ac=0 [(-3k)² - 4ac]=0 [9k²-32k] =0 9k²-32k=0 9k²=32k 9k*k=32k K=32k/9k k=32/9 or k=3.555..... approximately: 3.6

    1Thank You

    Amit Singh 6 years, 4 months ago

    X=12 therefore k=6

    0Thank You

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