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Solve by factorization method :abx square+(b …

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Solve by factorization method :abx square+(b square-ac)x-bc=0
  • 2 answers

Sia ? 6 years, 4 months ago

We have, abx2 + (b2 -ac) x-bc = 0
{tex}\implies{/tex}abx2 + b2 x - acx - bc = 0
{tex}\implies{/tex}bx ( ax+b) - c (ax + b) = 0
{tex}\implies{/tex}(ax + b) (bx - c) = 0
Either ax+b = 0 or bx - c = 0
{tex}\implies x = -{b \over a},\, {c \over b}{/tex}
Hence, {tex}x = -{b \over a},\, {c \over b}{/tex} are the required solutions.

Shravya Shetty 6 years, 4 months ago

Thanks
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