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Find the value of(3tan 41/cot 49)2 …

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Find the value of(3tan 41/cot 49)2 41

Posted by Shiksha P 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Gaurav Seth 6 years, 4 months ago

Full question: Find the value of: (3 tan 41/cot 49)^2 - (sin35sec55/tan10tan20tan60tan70tan80)^2

Answer:

26/3

Step-by-step explanation:

Given find the value of:

(3 tan 41/cot 49)^2 - (sin35 sec55 / tan10 tan20 tan60 tan70 tan80)^2

(3 tan 41 / cot (90 - 41) - sin 35 sec(90 - 35) / tan 10. tan 20. tan 60 . tan(90 - 20) tan(90 - 10)

(3 tan 41 / tan 41)^2 - (sin 35 sec(90 - 35) / tan 10 tan 20 tan 60 tan(90 - 20)tan(90 - 10))^2

(3 x 1)^2 - (sin 35 cosec 35 / tan 10. cot 10. tan 20. cot 20. tan 60)^2

9 - (1 / 1 x 1 x √3)^2 (because cosec 35 = 1/sin35)

9 - 1 / 3

27 - 1 / 3

26 / 3

1Thank You

ANSWER

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