A small telescope has an objective …
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Sia ? 6 years, 6 months ago
Given, focal length of objective lens, f0= 144 cm
Focal length of eyepiece, fe = 6 cm
Magnifying power of the telescope in normal adjustment,(i.e. when the final image is formed at {tex}\infty{/tex})
M = {tex}- \frac { f _ { 0 } } { f _ { e } } = - \frac { 144 } { 6 } = - 24{/tex}
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