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Three identical cells ,each of emf …

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Three identical cells ,each of emf 2V and internal resistance 0.2 ohm ,are connected in series to an external resistor of 7.4 ohm.calculate the current in circuit and the terminal potential diffrence across an equivalent cell.

    • Posted by Aishwarya Panda 6 years, 6 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Dr.Niraj Kumar 6 years, 6 months ago

    Net EMF of the cell=2*3=6
    Total resistance o the circuit=0.2+0.2+0.2+7.4=8
    Therefore,I=nE/R+nR=6/8=0.75A

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