Show that impulse of a variable …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Gautam Summan 6 years, 4 months ago
- 1 answers
Related Questions
Posted by Pankaj Tripathi 1 year, 5 months ago
- 1 answers
Posted by Mansi Class 9Th 1 year, 5 months ago
- 0 answers
Posted by Nekita Baraily 1 year, 4 months ago
- 2 answers
Posted by Mohammed Javith 1 year, 5 months ago
- 0 answers
Posted by M D 1 year, 4 months ago
- 1 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 6 years, 4 months ago
A variable force is a force whose magnitude or direction or both vary during the displacement of a body on which it acts or a force whose direction or magnitude or both change with time.
The graphical representation is given as:
Consider a small displacement element {tex}\Delta s{/tex} under force F, which is represented by a strip KLMN. As the displacement {tex}\Delta{/tex}s is extremely small, hence force F for entire strip KLMN may be taken as constant.
Therefore, Work done during elementary expansion will be equal to
{tex}\Delta W =F\Delta x{/tex}= area of strip KLMN ....................................(A)
Total work done by the variable force can be calculated by dividing the whole path into such elementary parts and in each case the work done will be equal to area of small shaded strips like KLMN. Therefore, total work done for a given displacement is given by:
W = {tex}\sum \Delta W=\sum{/tex} area of various strips = total area under F-s graph .......................................(B)
Thus, the work done by a variable force is given by the area under F-s curve.
0Thank You