Imagine a square ABCD of side 'a'units. It's diagonals will be AC and BD. By Pythagoras theorem, AC^2=AB^2+BC^2 AC=(AB^2+BC^2)^1/2 AC=(a^2+a^2)^1/2 AC=(2a^2)^1/2 the diagonal of a square=(2^1/2)a.

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