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Express the HCF of 210 and …

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Express the HCF of 210 and 66 as 210x+66y, where x,y are integers

    • Posted by Jay Anth 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ram Kushwah 6 years, 4 months ago

    Applying Division lemma on 210 and 66

    210=66*3+2-----------(1)

    Applying Division lemma on 2 and 66

    66=2*33+0

    Here remainder is zero 

    so HCF(66,210)=2

    Now from(1)

    2=210-3*66

    HCF=210*1-3*66-----------------(2)

    Given HCF=210x+66y-------------(3)

    Comparing (2) and (3) we get

    x=1 and y=-3

    Hence  HCF=210*1-3*66

     

     

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