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A positive charge +Q is fixed …

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A positive charge +Q is fixed at a point in space. There is another charge -q, which moves in a circular path of radius r around the given fixed charge. Assume that the electrostatic force between them is the only force acting on them. Calculate time period of revolution of charge.

    • Posted by Anurag Gupta 6 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Dr.Niraj Kumar 6 years, 4 months ago

    Hey,if the charge is moving in circular path around a charge then it have centripetal force. And if the distance between them is not decreasing then, electrostatic force=centripetal force. Therefore,kq1×q2/r^2=mrω^2 As ω=(2π/T) Therefore,kq1×q2/r^2=mr(2π/T)^2 kq1×q2/r^2=mr4π^2/T^2 Further,solve the equation obtained and find the value of T=period of revolution,if you are really curious about this question..

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