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Find the no. Of electrons present …

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Find the no. Of electrons present in an 8g gold pin. Given ; electrons per atom in gold = 79. And molar mass of gold. 197g/mol. And avogadro no. 6.023×10**23

    • Posted by Anurag Gupta 6 years, 6 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Dr.Niraj Kumar 6 years, 6 months ago

    1mol=79x6.023x10^23e Mol=mass given÷molar mass Mol=8÷197=0.041 Total electorn in 8g gold= 0.041x79x6.023x10^23 =193.55x10^22e

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