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The taxi fare in a city …

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The taxi fare in a city is as follows:Far the first kilometer,the fare is 8₹ and for the sibsequent distance it is ₹5 per kilometer .Taking the distance covered as x kilometer and total fare as ₹ y, wriye the linner equation for this information,draw a graph.

Posted by Raghupathy Natarajan 6 years, 4 months ago

CBSE > Class 09 > Mathematics

4 answers

Tanvi Toor 6 years, 4 months ago

It na asan questions ?????

Gaurav Seth 6 years, 4 months ago

Given,Total distance covered= x km=1+(x-1)km

Fare For first kilometre= ₹8

Fare for subsequent distance= ₹5 per km

Fare for next(x-1)km= 5(x-1)

A.T.Q

Total fare= y

8+5(x-1)=y

8+5x-5=y

5x-y+3=0

Which is the required linear equation.

It can also be written as y= 5x+3

When X = 0 ,then Y = 3,When x=1, then y= 5+3=8

When x= 2, then y= 10+3=13

Now plot the points A(0,3), B(1,8), C( 2,13) on the graph paper and join them to form a line BC, which represents the required graph of linear equation.

Raj Kumar 6 years, 4 months ago

Mai tume baad me sahi tarike se solve karunga, tab tak ke liye bye - bye

Raj Kumar 6 years, 4 months ago

Equation is : 5x + 3 = y. And solve it

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Few rules to keep homework help section safe, clean and informative.

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