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age of father (y)is 8 less than 5 times the age of his son (x) . find this situation by linear equation in two variable?

Posted by Ahil Shalideen 6 years, 4 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let the age of father is x years and that of son is y years.
Then by the given question,

Two years ago father was five times as old as his son
{tex}x-2=5(y-2){/tex}
or, {tex}x-5y=-10+2{/tex}
or, {tex}x-5y=-8{/tex}
or, {tex}x=5y-8{/tex}

Two years later, his age will be 8 years more than three times the age of the son
{tex}x+2=3(y+2)+8{/tex}
or, {tex}x-3y=6+8-2{/tex}
or, {tex}5y-8-3y=12{/tex}
or, {tex}2y=12+8{/tex}
or, {tex}y=\frac{20}{2}{/tex}
or, {tex}y=10{/tex}
then x=5y-8=50-8=42
Then, the age of father is 42 yrs. and the age of son is 10 yrs.

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